Comment by periblepsis on Using the Extra Element Theorem on Bandpass Filter
Well, I get a numerator with only a 2nd order s term and a denominator of 4th order. solve(Eq(vout/zl+vout/(s*l4)+vout*s*c3+vout/(s*l1+1/s/c2),vi‌​n/(s*l1+1/s/c2)),vou‌​t)[0]/vin =...
View ArticleComment by periblepsis on Discrepancy between AC analysis and transient...
AC analysis is small signal analysis. Such linear analysis doesn't notice clipping or non-linear PN junctions. The diodes might look like resistors/capacitors in AC analysis if they were biased with a...
View ArticleComment by periblepsis on Transistor Testing Circuit
@DNEME The only complaint I have about your description (or Hacktastical's acceptance of it) is that it is the NPN base current that causes the capacitor's high, early discharge rate. Once the...
View ArticleComment by periblepsis on Simulating the Howland Current Pump in Real-World...
Step 1: Check the output voltage swing on your ideal opamp with your circuit. What did you get there? Is it within the rails you provided your opamp in the non-ideal case? Step 2: Did you do the math?...
View ArticleComment by periblepsis on Control to output transfer function - Ltspice...
@Mhan AC analysis is small signal analysis, aka linear analysis. An ITS step is performed to get DC operating points, first. Walk us through that initial transient solution.
View ArticleComment by periblepsis on RISC-V Exercise: why is `MemtoReg = 1`?
RegWrite will be 0. So no worries.
View ArticleAnswer by periblepsis for Simulating the Howland Current Pump in Real-World...
If you perform the following:eqplus = Eq( vp/r16 + vp/r15 + vp/r17, vin/r16 + vout/r15 ) # (+) KCLeqminus = Eq( vm/r13 + vm/r14, vout/r14 ) # (-) KCLeqout = Eq( vout/r15 + vout/r14, vm/r14 + vp/r15 +...
View ArticleComment by periblepsis on DAC Based current source not working as expected
Looks like the simulation is right. Why do you imagine, in any possible way, that using a 322.9k resistor on one side with a 2k resistor on the other would do anything else? What is 2.3 uA times 322.9k...
View ArticleComment by periblepsis on How do I calculate the output voltage of this...
Do you want a closed solution using the Shockley equation? Or is your diode some kind of ideal type? The math is a little tricky if you want something close to reality. Otherwise, if you don't care...
View ArticleComment by periblepsis on Differential Amplifier: Common-mode rejection
Given the schematic, the \$V_{_\text{BE}}\$ of one bipolar must be the same as the \$V_{_\text{BE}}\$ of the other. The bases and emitters are wired together. And with the ideal emitter current sink...
View ArticleComment by periblepsis on Differential Amplifier: Common-mode rejection
The bases are wired together. The emitters are wired together. Both bipolars have the exact same \$V_{_\text{BE}}\$. In the ideal active-mode case, assuming they aren't driven into saturation by the...
View ArticleComment by periblepsis on Transistor convert pure square wave signal into...
Hrmann, You have said what you are getting, but you have not said what you want to have. Given we don't know what you want, it is rather more difficult then to tell you what you may be doing wrong. Are...
View ArticleComment by periblepsis on Transistor convert pure square wave signal into...
Those were, back at least as far as when I was a child in the 1960's, called speed up's. +1 for suggesting it. I think I'll build on what you wrote here (which is a fine idea) since you've reminded me.
View ArticleComment by periblepsis on How am I supposed to drive 50-Ohm terminated "CMOS...
Consider using the schmitt inverters in the 74AC14. This video on making a TDR provides some details. Not promising a fit, just suggesting something to consider.
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Answer by periblepsis for Can I simplify a half-adder when using only NAND...
My question is, assuming my work above is correct, can simplify my drawingof half-adders by using (xy')' (x'y)'immediately once I find them, and passing them through one more NAND gate toarrive at...
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Answer by periblepsis for Transistor convert pure square wave signal into...
A 555 timer already has a fairly capable 2-quadrant output. One that is much better than your single bipolar with a resistor for its output. Partly for that reason, it wasn't clear to me where you are...
View ArticleComment by periblepsis on Solving for currents in diode circuit
@psich No problem. :) Often, it's just little details like that. It takes practice to reduce these kinds of sign errors. (Never quite get to zero of them, though. So finding ways to cross-check is a...
View ArticleComment by periblepsis on Calculating Thevenin's resistance in circuits with...
But you can add a current source to those terminals to work out the Thevenin resistance. Why don't you think so?
View ArticleComment by periblepsis on Introduction to Electronics 6th Current vs. Current...
Anakin, I suggest to get and read Matter & Interactions by Chabay and Sherwood. 3rd or 4th edition. It's very accessible and will take you from "knowing nothing much" to having a pretty good handle...
View ArticleComment by periblepsis on APD active quenching circuit - please help to...
Your quench source isn't representative, to start. There is a dark current, which at -10 C and a reasonable over-voltage looks about like 100 nA from figure 3. A single photon doesn't have "watts" but...
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