solve([Eq(vb/82e3+vb/24e3+ib,16/82e3),Eq((vb-0.7)/re,151*ib),Eq(150*ib,(16-6)/5.6e3)],[ib,re,vb]) gives [(1.19047619047619e-5, 1502.88641759340, 3.40161725067385)]. Many approaches with this problem.
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Comment by periblepsis on Are the steps in my solution for this BJT circuit correct?
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