I don't see a good way to write an answer. You write, "but why would it be close to zero if it is a short circuit?", referring to the first diagram. I guess you imagine a "short" since the base is tied directly to the divider with a wire and conclude there is a very high resistance inside the base. You then posit a new schematic with no emitter resistor and a different base arrangement to see if you are right. But the impedance looking into the base (with respect to some point) depends in some large part upon the emitter resistor, which you just removed. Can you clarify your thoughts for me?
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